If $$k=\frac{(6x)}{7}$$ and $$k\nwq0$$, then $$\frac{(2x)}{(7k)}=

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If $$k=\frac{(6x)}{7}$$ and $$k\nwq0$$, then $$\frac{(2x)}{(7k)}=$$

A、$$\frac{1}{6}$$
B、$$\frac{12}{49}$$
C、$$\frac{2}{7}$$
D、$$\frac{1}{3}$$
E、$$\frac{6}{7}$$

答案：D

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